Questions: Find the domain of the function (f(x)=sqrt5x-2)
In interval form, the domain of (f) is (square)
Transcript text: Find the domain of the function $f(x)=\sqrt{5 x-2}$
In interval form, the domain of $f$ is $\square$
Solution
Solution Steps
To find the domain of the function \( f(x) = \sqrt{5x - 2} \), we need to determine the values of \( x \) for which the expression under the square root is non-negative. This means solving the inequality \( 5x - 2 \geq 0 \).
Step 1: Understand the Problem
We need to find the domain of the function \( f(x) = \sqrt{5x - 2} \). The domain of a function is the set of all possible input values (x-values) that make the function defined.
Step 2: Identify the Condition for the Square Root Function
For the square root function \( \sqrt{5x - 2} \) to be defined, the expression inside the square root must be non-negative. Therefore, we need:
\[ 5x - 2 \geq 0 \]
Step 3: Solve the Inequality
Solve the inequality \( 5x - 2 \geq 0 \):
\[
5x - 2 \geq 0
\]
Add 2 to both sides:
\[
5x \geq 2
\]
Divide both sides by 5:
\[
x \geq \frac{2}{5}
\]
Step 4: Express the Domain in Interval Form
The domain of \( f(x) \) is all \( x \) such that \( x \geq \frac{2}{5} \). In interval notation, this is:
\[
\left[ \frac{2}{5}, \infty \right)
\]
Final Answer
The domain of \( f \) in interval form is:
\[
\boxed{\left[ \frac{2}{5}, \infty \right)}
\]