Questions: Consider the following Verilog code. Which statement(s) is (are) correct? Select all that apply. ``` module M1 (F, A, B, C, D, E); output F ; input A,B,C,D,E; wire w1,w2; nor (w1,A,B); nor (w2,C,D); SubM0 M0 (F,w1,w2,E); endmodule ``` module SubM0(output y,input x1,x2,x3); assign y=(!x1) (!x2) (!x3); endmodule

Consider the following Verilog code. Which statement(s) is (are) correct? Select all that apply.

```
module M1 (F, A, B, C, D, E);
    output F ;
    input A,B,C,D,E;
    wire w1,w2;
    nor (w1,A,B);
    nor (w2,C,D);
    SubM0 M0 (F,w1,w2,E);
endmodule
```
module SubM0(output y,input x1,x2,x3); assign y=(!x1) (!x2) (!x3); endmodule
Transcript text: Consider the following Verilog code. Which statement(s) is (are) correct? Select all that apply. ``` module M1 ( $\mathrm{F}, \mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E})$; output F ; input A,B,C,D,E; wire w1,w2; nor (w1,A,B); nor (w2,C,D); SubM0 M0 (F,w1,w2,E); endmodule ``` module SubM0(output y,input x1,x2,x3); assign $\underline{y}=(!\mathrm{x} 1) \& \&(!\mathrm{x} 2) \& \&(!\mathrm{x} 3)$; endmodule
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Solution

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Solution Steps

Step 1: Understand the Verilog Code

The given Verilog code consists of two modules: M1 and SubM0. The M1 module has inputs A, B, C, D, E and an output F. It also declares two wires w1 and w2. The nor gates are used to assign values to w1 and w2. The SubM0 module is instantiated within M1 and connects F, w1, w2, and E.

Step 2: Analyze the M1 Module
  • nor (w1, A, B); computes the NOR of A and B and assigns it to w1.
  • nor (w2, C, D); computes the NOR of C and D and assigns it to w2.
  • SubM0 M0(F, w1, w2, E); instantiates SubM0 with F as the output and w1, w2, E as inputs.
Step 3: Analyze the SubM0 Module
  • assign y = (!x1) && (!x2) && (!x3); computes the AND of the negations of x1, x2, and x3 and assigns it to y.

Final Answer

The correct statements about the Verilog code are:

  • The M1 module correctly instantiates the SubM0 module.
  • The SubM0 module correctly computes the AND of the negations of its inputs.

Thus, the correct statements are:

  1. The M1 module correctly instantiates the SubM0 module.
  2. The SubM0 module correctly computes the AND of the negations of its inputs.
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