Questions: Graf ktorej z nasledujúcich funkcií má na intervale ⟨0,2 π⟩ najviac priesečníkov s osou x ?
(A) f1: y=2+sin x
(B) f2: y=2 sin x
(C) f3: y=sin (x/2)
(D) f4: y=sin 2x
(E) f5: y=sin x
Transcript text: Graf ktorej $z$ nasledujúcich funkcií má na intervale $\langle 0,2 \pi\rangle$ najviac priesečníkov s osou $x$ ?
(A) $f_{1}: y=2+\sin x$
(B) $f_{2}: y=2 \sin x$
(C) $f_{3}: y=\sin \frac{x}{2}$
(D) $f_{4}: y=\sin 2 x$
(E) $f_{5}: y=\sin x$
Solution
Solution Steps
To determine which function has the fewest intersections with the x-axis on the interval ⟨0,2π⟩, we need to find the number of roots (or zeros) of each function within this interval. A function intersects the x-axis where its value is zero. We will evaluate each function to find the number of such points.
Step 1: Identify the Functions
We are given five functions to analyze for their intersections with the x-axis on the interval ⟨0,2π⟩:
f1:y=2+sinx
f2:y=2sinx
f3:y=sin2x
f4:y=sin2x
f5:y=sinx
Step 2: Count the Intersections
We evaluate each function to determine the number of roots (intersections with the x-axis) within the specified interval:
For f1, 2+sinx=0 has 0 intersections.
For f2, 2sinx=0 has 2 intersections.
For f3, sin2x=0 has 2 intersections.
For f4, sin2x=0 has 2 intersections.
For f5, sinx=0 has 2 intersections.
Step 3: Determine the Function with the Fewest Intersections
From the counts:
f1: 0 intersections
f2: 2 intersections
f3: 2 intersections
f4: 2 intersections
f5: 2 intersections
The function f1 has the fewest intersections with the x-axis.
Final Answer
The function with the fewest intersections with the x-axis on the interval ⟨0,2π⟩ is f1.