Questions: Divide the expression. (8 x^3+14 x^2-8 x-14)/(2 x^2-2)

Divide the expression.
(8 x^3+14 x^2-8 x-14)/(2 x^2-2)
Transcript text: Divide the expression. \[ \frac{8 x^{3}+14 x^{2}-8 x-14}{2 x^{2}-2} \]
failed

Solution

failed
failed

Solution Steps

To divide the given polynomial expression, we can perform polynomial long division. We will divide the numerator \(8x^3 + 14x^2 - 8x - 14\) by the denominator \(2x^2 - 2\).

Step 1: Define the Expression

We start with the polynomial expression to be divided: \[ \frac{8x^3 + 14x^2 - 8x - 14}{2x^2 - 2} \]

Step 2: Perform Polynomial Long Division

We divide the numerator \(8x^3 + 14x^2 - 8x - 14\) by the denominator \(2x^2 - 2\).

  1. The leading term of the numerator \(8x^3\) divided by the leading term of the denominator \(2x^2\) gives us \(4x\).
  2. Multiply \(4x\) by the entire denominator: \[ 4x(2x^2 - 2) = 8x^3 - 8x \]
  3. Subtract this from the original numerator: \[ (8x^3 + 14x^2 - 8x - 14) - (8x^3 - 8x) = 14x^2 - 14 \]
Step 3: Continue the Division

Now, we divide \(14x^2 - 14\) by \(2x^2 - 2\):

  1. The leading term \(14x^2\) divided by \(2x^2\) gives us \(7\).
  2. Multiply \(7\) by the entire denominator: \[ 7(2x^2 - 2) = 14x^2 - 14 \]
  3. Subtract this from the previous result: \[ (14x^2 - 14) - (14x^2 - 14) = 0 \]

Final Answer

The quotient of the division is: \[ \boxed{4x + 7} \] with a remainder of \(0\).

Was this solution helpful?
failed
Unhelpful
failed
Helpful