Questions: The diameter of the nucleus of an atom is approximately 1 x 10^-15 meters. If 1 nm is equal to 10 Angstroms, what is the diameter of the nucleus in Angstroms? A) 1 x 10^-23 Å B) 1 x 10^-7 Å C) 1 x 10^-8 Å D) 1 x 10^-5 Å

Solution Steps

The diameter of the nucleus is given as \(1 \times 10^{-15}\) meters. To convert this to nanometers (nm), we use the conversion factor \(1 \, \text{nm} = 1 \times 10^{-9}\) meters.

\[ \text{Diameter in nm} = \frac{1 \times 10^{-15} \, \text{meters}}{1 \times 10^{-9} \, \text{meters/nm}} = 1 \times 10^{-6} \, \text{nm} \]

We know that \(1 \, \text{nm} = 10 \, \text{Å}\). Therefore, to convert the diameter from nanometers to Angstroms, we multiply by 10.

\[ \text{Diameter in Å} = 1 \times 10^{-6} \, \text{nm} \times 10 \, \text{Å/nm} = 1 \times 10^{-5} \, \text{Å} \]

Final Answer