Questions: A certain shade of blue has a frequency of 7.23 × 10^14 Hz. What is the energy of exactly one photon of this light? Planck's
Transcript text: A certain shade of blue has a frequency of $7.23 \times 10^{14} \mathrm{~Hz}$. What is the energy of exactly one photon of this light? Planck's
\[
E=
\]
Solution
Solution Steps
Step 1: Identify the Given Information
We are given the frequency of a certain shade of blue light as \(7.23 \times 10^{14} \, \text{Hz}\).
Step 2: Recall the Formula for Photon Energy
The energy of a photon can be calculated using Planck's equation:
\[
E = h \cdot f
\]
where \(E\) is the energy of the photon, \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J}\cdot\text{s}\)), and \(f\) is the frequency of the light.
Step 3: Substitute the Given Values into the Formula
Substitute the given frequency and Planck's constant into the formula:
\[
E = (6.626 \times 10^{-34} \, \text{J}\cdot\text{s}) \cdot (7.23 \times 10^{14} \, \text{Hz})
\]
Step 4: Calculate the Energy
Perform the multiplication to find the energy:
\[
E = 4.791 \times 10^{-19} \, \text{J}
\]
Final Answer
The energy of exactly one photon of this light is \(\boxed{4.791 \times 10^{-19} \, \text{J}}\).