Find the particular solution of the differential equation given the initial condition.
Separate the variables.
Given the differential equation:
\[
\frac{12}{x} \frac{d y}{d x}=\frac{6}{y}
\]
Rearrange to separate variables:
\[
12y \, dy = 6x \, dx
\]
Simplify:
\[
2y \, dy = x \, dx
\]
Integrate both sides.
Integrate the separated equation:
\[
\int 2y \, dy = \int x \, dx
\]
This results in:
\[
y^2 = \frac{x^2}{2} + C
\]
Solve for \(y\).
Isolate \(y\):
\[
y = \pm \sqrt{\frac{x^2}{2} + C}
\]
Apply the initial condition.
Given the point \((3, 2)\), substitute \(x = 3\) and \(y = 2\):
\[
2 = \pm \sqrt{\frac{3^2}{2} + C}
\]
\[
2 = \pm \sqrt{\frac{9}{2} + C}
\]
Square both sides:
\[
4 = \frac{9}{2} + C
\]
Solve for \(C\):
\[
C = 4 - \frac{9}{2} = \frac{8}{2} - \frac{9}{2} = -\frac{1}{2}
\]
Since \(y=2\) is positive, take the positive square root.
Write the particular solution.
Substitute \(C = -\frac{1}{2}\) back into the equation:
\[
y = \sqrt{\frac{x^2}{2} - \frac{1}{2}}
\]
Simplify:
\[
y = \sqrt{\frac{x^2 - 1}{2}}
\]
\(\boxed{y = \sqrt{\frac{x^2 - 1}{2}}}\)
\(\boxed{y = \sqrt{\frac{x^2 - 1}{2}}}\)