Questions: Directions: In this problem we are going to calculate the derivative of tan(x) using the Quotient Rule. For Steps 1-3, leave your answers in terms of sin x and cos x.
Step 1: Write tan(x) in terms of sin(x) and cos(x).
tan(x)=
Step 2: Calculate the derivative of this expression using the Quotient Rule. Once you differentiate, it may be helpful to remember the trig identity: sin^2(x)+cos^2(x)=1.
d/dx[tan(x)]=
Step 3: Rewrite your expression from step 2 in the following format.
d/dx[tan(x)]=1/cos(x)
Step 4: Finally, rewrite this expression in terms of sec(x) and tan(x).
d/dx[tan(x)]=
Transcript text: Directions: In this problem we are going to calculate the derivative of $\tan (x)$ using the Quotient Rule. For Steps $1-3$, leave your answers in terms of $\sin x$ and $\cos x$.
Step 1: Write $\tan (x)$ in terms of $\sin (x)$ and $\cos (x)$.
\[
\tan (x)=
\]
$\square$
$\square$
$\square$
Step 2: Calculate the derivative of this expression using the Quotient Rule. Once you differentiate, it may be helpful to remember the trig identity: $\sin ^{2}(x)+\cos ^{2}(x)=1$.
$\square$
\[
\frac{d}{d x}[\tan (x)]=
\]
$\square$
$\square$
Step 3: Rewrite your expression from step 2 in the following format.
\[
\frac{d}{d x}[\tan (x)]=\frac{1}{\cos (x)}
\]
$\square$
$\square$
$\square$
Step 4: Finally, rewrite this expression in terms of $\sec (x)$ and $\tan (x)$.
\[
\frac{d}{d x}[\tan (x)]=\square
\]
Solution
Solution Steps
Step 1: Express \(\tan(x)\)
We can express \(\tan(x)\) in terms of \(\sin(x)\) and \(\cos(x)\) as follows:
\[
\tan(x) = \frac{\sin(x)}{\cos(x)}
\]
Step 2: Calculate the Derivative
Using the Quotient Rule, the derivative of \(\tan(x)\) is calculated as:
\[
\frac{d}{dx}[\tan(x)] = \frac{\sin^2(x)}{\cos^2(x)} + 1
\]
Step 3: Simplify the Derivative
By simplifying the expression, we find:
\[
\frac{d}{dx}[\tan(x)] = \cos(x)^{-2}
\]
Step 4: Rewrite in Terms of \(\sec(x)\)
Recognizing that \(\sec(x) = \frac{1}{\cos(x)}\), we can rewrite the derivative as:
\[
\frac{d}{dx}[\tan(x)] = \sec^2(x)
\]
Final Answer
Thus, the derivative of \(\tan(x)\) is:
\[
\boxed{\frac{d}{dx}[\tan(x)] = \sec^2(x)}
\]