To convert joules to calories, use the conversion factor \(1 \, \text{cal} = 4.184 \, \text{J}\).
Given: \(5.38 \times 10^{-2} \, \text{J}\)
\[
\text{cal} = \frac{5.38 \times 10^{-2} \, \text{J}}{4.184 \, \text{J/cal}} = 1.286 \times 10^{-2} \, \text{cal}
\]
This value is approximately \(1.29 \times 10^{-2} \, \text{cal}\), which matches the given value in the table.
To convert kilowatt-hours to joules, use the conversion factor \(1 \, \text{kWh} = 3.60 \times 10^{6} \, \text{J}\).
Given: \(125 \, \text{kWh}\)
\[
\text{J} = 125 \, \text{kWh} \times 3.60 \times 10^{6} \, \text{J/kWh} = 4.50 \times 10^{8} \, \text{J}
\]
First, convert joules to calories using the conversion factor \(1 \, \text{cal} = 4.184 \, \text{J}\).
\[
\text{cal} = \frac{4.50 \times 10^{8} \, \text{J}}{4.184 \, \text{J/cal}} = 1.075 \times 10^{8} \, \text{cal}
\]
Next, convert calories to Calories using the conversion factor \(1 \, \text{Cal} = 1000 \, \text{cal}\).
\[
\text{Cal} = \frac{1.075 \times 10^{8} \, \text{cal}}{1000 \, \text{cal/Cal}} = 1.075 \times 10^{5} \, \text{Cal}
\]
\[
\begin{array}{|c|c|c|c|}
\hline
\text{J} & \text{cal} & \text{Cal} & \text{kWh} \\
\hline
5.38 \times 10^{-2} & 1.29 \times 10^{-2} & & \\
\hline
4.50 \times 10^{8} & 1.075 \times 10^{8} & 1.075 \times 10^{5} & 125 \\
\hline
\end{array}
\]
\[
\boxed{
\begin{array}{|c|c|c|c|}
\hline
\text{J} & \text{cal} & \text{Cal} & \text{kWh} \\
\hline
5.38 \times 10^{-2} & 1.29 \times 10^{-2} & & \\
\hline
4.50 \times 10^{8} & 1.075 \times 10^{8} & 1.075 \times 10^{5} & 125 \\
\hline
\end{array}
}
\]