Questions: V=(h^3-3)(2h^2-2h-3)

V=(h^3-3)(2h^2-2h-3)
Transcript text: $V=\left(h^{3}-3\right)\left(2 h^{2}-2 h-3\right)$
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Solution

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Solution Steps

To solve the expression for \( V = (h^3 - 3)(2h^2 - 2h - 3) \), we need to expand the product of the two polynomials. This involves distributing each term in the first polynomial by each term in the second polynomial and then combining like terms.

Step 1: Expand the Expression

To find the expanded form of the expression \( V = (h^3 - 3)(2h^2 - 2h - 3) \), we distribute each term in the first polynomial by each term in the second polynomial. This involves multiplying each term in \( h^3 - 3 \) by each term in \( 2h^2 - 2h - 3 \).

Step 2: Combine Like Terms

After distributing, we combine like terms to simplify the expression. The expanded form of the expression is:

\[ V = 2h^5 - 2h^4 - 3h^3 - 6h^2 + 6h + 9 \]

Final Answer

\(\boxed{V = 2h^5 - 2h^4 - 3h^3 - 6h^2 + 6h + 9}\)

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