Questions: Find the zeros of the function. Give exact solutions.
x^2 + 7x - 5 = 0
The exact solutions are x =
(Simplify your answer. Use integers or f as needed.)
Transcript text: Find the zeros of the function. Give exact solutions.
\[
x^{2}+7 x-5=0
\]
The exact solutions are $x=$ $\square$
(Simplify your answer. Use integers or $f$ as needed.)
Solution
Solution Steps
To find the zeros of the quadratic function \(x^2 + 7x - 5 = 0\), we can use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are the coefficients of the quadratic equation \(ax^2 + bx + c = 0\).
Step 1: Identify the Coefficients
Given the quadratic equation \(x^2 + 7x - 5 = 0\), we identify the coefficients:
\(a = 1\)
\(b = 7\)
\(c = -5\)
Step 2: Calculate the Discriminant
The discriminant \(\Delta\) of the quadratic equation is given by:
\[
\Delta = b^2 - 4ac
\]
Substituting the values of \(a\), \(b\), and \(c\):
\[
\Delta = 7^2 - 4 \cdot 1 \cdot (-5) = 49 + 20 = 69
\]
Step 3: Apply the Quadratic Formula
The solutions to the quadratic equation are given by:
\[
x = \frac{-b \pm \sqrt{\Delta}}{2a}
\]
Substituting the values of \(a\), \(b\), and \(\Delta\):
\[
x = \frac{-7 \pm \sqrt{69}}{2 \cdot 1}
\]
Step 4: Calculate the Exact Solutions
We calculate the two solutions:
\[
x_1 = \frac{-7 + \sqrt{69}}{2} \approx 0.6533
\]
\[
x_2 = \frac{-7 - \sqrt{69}}{2} \approx -7.6533
\]
Final Answer
The exact solutions are:
\[
\boxed{x = \frac{-7 + \sqrt{69}}{2} \text{ and } x = \frac{-7 - \sqrt{69}}{2}}
\]