Questions: Find the zeros of the function. Give exact solutions. x^2 + 7x - 5 = 0 The exact solutions are x = (Simplify your answer. Use integers or f as needed.)

Find the zeros of the function. Give exact solutions.

x^2 + 7x - 5 = 0

The exact solutions are x = 

(Simplify your answer. Use integers or f as needed.)
Transcript text: Find the zeros of the function. Give exact solutions. \[ x^{2}+7 x-5=0 \] The exact solutions are $x=$ $\square$ (Simplify your answer. Use integers or $f$ as needed.)
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Solution

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Solution Steps

To find the zeros of the quadratic function \(x^2 + 7x - 5 = 0\), we can use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a\), \(b\), and \(c\) are the coefficients of the quadratic equation \(ax^2 + bx + c = 0\).

Step 1: Identify the Coefficients

Given the quadratic equation \(x^2 + 7x - 5 = 0\), we identify the coefficients:

  • \(a = 1\)
  • \(b = 7\)
  • \(c = -5\)
Step 2: Calculate the Discriminant

The discriminant \(\Delta\) of the quadratic equation is given by: \[ \Delta = b^2 - 4ac \] Substituting the values of \(a\), \(b\), and \(c\): \[ \Delta = 7^2 - 4 \cdot 1 \cdot (-5) = 49 + 20 = 69 \]

Step 3: Apply the Quadratic Formula

The solutions to the quadratic equation are given by: \[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \] Substituting the values of \(a\), \(b\), and \(\Delta\): \[ x = \frac{-7 \pm \sqrt{69}}{2 \cdot 1} \]

Step 4: Calculate the Exact Solutions

We calculate the two solutions: \[ x_1 = \frac{-7 + \sqrt{69}}{2} \approx 0.6533 \] \[ x_2 = \frac{-7 - \sqrt{69}}{2} \approx -7.6533 \]

Final Answer

The exact solutions are: \[ \boxed{x = \frac{-7 + \sqrt{69}}{2} \text{ and } x = \frac{-7 - \sqrt{69}}{2}} \]

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