Questions: Based on the given van der Waals constants, arrange these hypothetical gases in order of decreasing strength of intermolecular forces. Assume that the gases have similar molar masses.
Rank from strongest to weakest intermolecular attraction. To rank items as equivalent, overlap them.
Gas D
Gas R
Gas Q
Gas M
Strongest attraction
Weakest attraction
Transcript text: Based on the given van der Waals constants, arrange these hypothetical gases in order of decreasing strength of intermolecular forces. Assume that the gases have similar molar masses.
Rank from strongest to weakest intermolecular attraction. To rank items as equivalent, overlap them.
Gas D
Gas R
Gas Q
Gas M
Strongest attraction
Weakest attraction
Solution
Solution Steps
Step 1: Understanding van der Waals Constants
The van der Waals equation is given by:
\[
\left( P + \frac{a}{V^2} \right) (V - b) = RT
\]
where \(a\) and \(b\) are van der Waals constants. The constant \(a\) accounts for the strength of intermolecular forces, while \(b\) accounts for the volume occupied by gas molecules.
Step 2: Identifying Relevant Constant
Since we are interested in the strength of intermolecular forces, we focus on the constant \(a\). A higher value of \(a\) indicates stronger intermolecular attractions.
Step 3: Arranging Gases by \(a\) Values
Assuming we have the \(a\) values for the gases (hypothetical values for illustration):