Questions: (3t+3)/(t-6) * (t^2-t-30)

(3t+3)/(t-6) * (t^2-t-30)
Transcript text: \[ \frac{3 t+3}{t-6} \cdot\left(t^{2}-t-30\right) \]
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Solution

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Solution Steps

To solve the given problem, we need to multiply the two expressions and simplify the result. The first step is to factorize both the numerator and the denominator where possible. Then, we can cancel out any common factors to simplify the expression.

Solution Approach
  1. Factorize the numerator and the denominator of the given fractions.
  2. Multiply the fractions.
  3. Simplify the resulting expression by canceling out common factors.
Step 1: Factor the Expressions

We start with the expression

\[ \frac{3t + 3}{t - 6} \cdot (t^2 - t - 30). \]

First, we factor the numerator \(3t + 3\) and the quadratic \(t^2 - t - 30\):

\[ 3t + 3 = 3(t + 1), \]

and

\[ t^2 - t - 30 = (t - 6)(t + 5). \]

Step 2: Rewrite the Expression

Substituting the factored forms back into the expression, we have:

\[ \frac{3(t + 1)}{t - 6} \cdot (t - 6)(t + 5). \]

Step 3: Cancel Common Factors

Next, we can cancel the common factor \((t - 6)\) from the numerator and the denominator:

\[ 3(t + 1)(t + 5). \]

Step 4: Simplify the Result

The simplified expression is:

\[ 3(t + 1)(t + 5). \]

Final Answer

Thus, the final answer in factored form is

\[ \boxed{3(t + 1)(t + 5)}. \]

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