Questions: Matching 20 points Match each geometric sequence with corresponding nth term. Geometric Sequences A. 1, 3, 9, 27, ... B. 1, -2, 4, -8, ... nth Term I. (2/3)^n C. 1/2, 1/4, 1/8, 1/16, ... II. (3)^(n-1) D. 2/3, 4/9, 8/27, 16/81, ... III. (-2)^(n-1) IV. 1/2^n c. A. B. D.

Matching 20 points
Match each geometric sequence with corresponding nth term.
Geometric Sequences
A. 1, 3, 9, 27, ...
B. 1, -2, 4, -8, ...
nth Term
I. (2/3)^n
C. 1/2, 1/4, 1/8, 1/16, ...
II. (3)^(n-1)
D. 2/3, 4/9, 8/27, 16/81, ...
III. (-2)^(n-1)
IV. 1/2^n
c. 
A. 
B. 
D.
Transcript text: 4 Matching 20 points Match each geometric sequence with orresponding $n^{\text {th }}$ term. Geometric Sequences A. $1,3,9,27, \ldots$ B. $1,-2,4,-8, \ldots$ $n^{\text {th }}$ Term I. $\left(\frac{2}{3}\right)^{n}$ C. $\frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \ldots$ II. $(3)^{(n-1)}$ D. $\frac{2}{3}, \frac{4}{9}, \frac{8}{27}, \frac{16}{81}, \ldots$ III. $(-2)^{(n-1)}$ IV. $\frac{1}{2^{n}}$ c. $\qquad$ A. $\qquad$ $\square$ $\square$ B. $\qquad$ $\square$ D. $\qquad$
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Solution

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Solution Steps

To match each geometric sequence with its corresponding \( n^{\text{th}} \) term, we need to identify the common ratio for each sequence and then match it with the given formulas.

  • Sequence A: \( 1, 3, 9, 27, \ldots \)

    • Common ratio: \( 3 \)
    • \( n^{\text{th}} \) term: \( 3^{(n-1)} \)
  • Sequence B: \( 1, -2, 4, -8, \ldots \)

    • Common ratio: \( -2 \)
    • \( n^{\text{th}} \) term: \( (-2)^{(n-1)} \)
  • Sequence C: \( \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \ldots \)

    • Common ratio: \( \frac{1}{2} \)
    • \( n^{\text{th}} \) term: \( \frac{1}{2^n} \)
  • Sequence D: \( \frac{2}{3}, \frac{4}{9}, \frac{8}{27}, \frac{16}{81}, \ldots \)

    • Common ratio: \( \frac{2}{3} \)
    • \( n^{\text{th}} \) term: \( \left(\frac{2}{3}\right)^n \)
Solution Approach
  1. Identify the common ratio for each sequence.
  2. Match the common ratio with the given \( n^{\text{th}} \) term formulas.
Step 1: Identify the Sequences

We have the following geometric sequences:

  • \( A: 1, 3, 9, 27, \ldots \)
  • \( B: 1, -2, 4, -8, \ldots \)
  • \( C: \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \ldots \)
  • \( D: \frac{2}{3}, \frac{4}{9}, \frac{8}{27}, \frac{16}{81}, \ldots \)
Step 2: Determine the Common Ratios

For each sequence, we calculate the common ratio:

  • For sequence \( A \), the common ratio \( r_A = \frac{3}{1} = 3 \).
  • For sequence \( B \), the common ratio \( r_B = \frac{-2}{1} = -2 \).
  • For sequence \( C \), the common ratio \( r_C = \frac{\frac{1}{4}}{\frac{1}{2}} = \frac{1}{2} \).
  • For sequence \( D \), the common ratio \( r_D = \frac{\frac{4}{9}}{\frac{2}{3}} = \frac{2}{3} \).
Step 3: Match with \( n^{\text{th}} \) Terms

Now we match each sequence with its corresponding \( n^{\text{th}} \) term:

  • Sequence \( A \) corresponds to \( n^{\text{th}} \) term \( II: 3^{(n-1)} \).
  • Sequence \( B \) corresponds to \( n^{\text{th}} \) term \( III: (-2)^{(n-1)} \).
  • Sequence \( C \) corresponds to \( n^{\text{th}} \) term \( IV: \frac{1}{2^n} \).
  • Sequence \( D \) corresponds to \( n^{\text{th}} \) term \( I: \left(\frac{2}{3}\right)^n \).

Final Answer

The matches are:

  • \( A \) matches with \( II \)
  • \( B \) matches with \( III \)
  • \( C \) matches with \( IV \)
  • \( D \) matches with \( I \)

Thus, the final answer is: \[ \boxed{ \begin{array}{c} A: II \\ B: III \\ C: IV \\ D: I \end{array} } \]

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