A reaction is exothermic if it releases energy to the surroundings. In this case, the reaction is known to release 190 kJ of energy. Therefore, the reaction is exothermic.
Since the reaction is exothermic, it releases heat to the surroundings. The water bath, being part of the surroundings, will absorb this heat, causing its temperature to go up.
The system does 153 kJ of work on the piston. When work is done by the system on the surroundings, it typically involves expansion, meaning the piston moves out.
In an exothermic reaction, heat flows out of the system. Therefore, heat flows out of the gas mixture.
Using the first law of thermodynamics, which states that the change in internal energy (\(\Delta U\)) is equal to the heat added to the system (\(q\)) minus the work done by the system (\(w\)), we have:
\[
\Delta U = q - w
\]
Given that the reaction releases 190 kJ of energy, this is the change in internal energy (\(\Delta U = -190 \, \text{kJ}\)), and the work done by the system is 153 kJ (\(w = 153 \, \text{kJ}\)), we can solve for \(q\):
\[
-190 = q - 153
\]
\[
q = -190 + 153 = -37 \, \text{kJ}
\]
The negative sign indicates that 37 kJ of heat flows out of the system.
- The reaction is \(\boxed{\text{exothermic}}\).
- The temperature of the water bath goes \(\boxed{\text{up}}\).
- The piston moves \(\boxed{\text{out}}\).
- Heat flows \(\boxed{\text{out}}\) of the gas mixture.
- The amount of heat that flows is \(\boxed{37 \, \text{kJ}}\).