Questions: Consider the equilibrium reaction 4 A+B <=> 3 C Write the equation for the reverse reaction. reverse reaction: Write the equilibrium-constant expression in terms of [A] ;[B], and [C] for the reverse reaction. Answer Bank [B]^5 [C] [B]^3 [A]^3 [C]^4 [A] [A]^4 [B] [C]^3

Consider the equilibrium reaction 4 A+B <=> 3 C Write the equation for the reverse reaction. reverse reaction: Write the equilibrium-constant expression in terms of [A] ;[B], and [C] for the reverse reaction. Answer Bank [B]^5 [C] [B]^3 [A]^3 [C]^4 [A] [A]^4 [B] [C]^3
Transcript text: Consider the equilibrium reaction \[ 4 A+B \rightleftharpoons 3 C \] Write the equation for the reverse reaction. reverse reaction: $\square$ Write the equilibrium-constant expression in terms of $[\mathrm{A}] ;[\mathrm{B}]$, and $[\mathrm{C}]$ for the reverse reaction. \begin{tabular}{|c|c|c|} \hline \multicolumn{3}{|c|}{Answer Bank} \\ \hline $[B]^{5}$ & [C] & $[B]^{3}$ \\ \hline $[A]^{3}$ & $[C]^{4}$ & [A] \\ \hline $[A]^{4}$ & [B] & $[C]^{3}$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Reverse Reaction

The reverse reaction is simply the original reaction written backward.

$3C \rightleftharpoons 4A + B$

Step 2: Equilibrium Constant Expression

The equilibrium constant expression for the reverse reaction ($K_{reverse}$) is the product of the concentrations of the reactants raised to their respective stoichiometric coefficients divided by the product of the concentrations of the products raised to their respective stoichiometric coefficients.

Final Answer:

  • Reverse reaction: $3C \rightleftharpoons 4A + B$

  • $K_{reverse} = \frac{[A]^4[B]}{[C]^3}$

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