Questions: Find the area under the standard normal curve that lies between the following z-values. Round the answers to four decimal places. Part 1 of 2 (a) Find the area under the standard normal curve that lies between z=-2.49 and z=-0.42. The area between z=-2.49 and z=-0.42 is .3309 Part 2 of 2 (b) Find the area under the standard normal curve that lies between z=-2.27 and z=0.36. The area between z=-2.27 and z=0.36 is .

Find the area under the standard normal curve that lies between the following z-values. Round the answers to four decimal places.

Part 1 of 2
(a) Find the area under the standard normal curve that lies between z=-2.49 and z=-0.42.

The area between z=-2.49 and z=-0.42 is .3309

Part 2 of 2
(b) Find the area under the standard normal curve that lies between z=-2.27 and z=0.36.

The area between z=-2.27 and z=0.36 is .
Transcript text: Find the area under the standard normal curve that lies between the following $z$-values. Round the answers to four decimal places. Part 1 of 2 (a) Find the area under the standard normal curve that lies between $z=-2.49$ and $z=-0.42$. The area between $z=-2.49$ and $z=-0.42$ is .3309 Part 2 of 2 (b) Find the area under the standard normal curve that lies between $z=-2.27$ and $z=0.36$. The area between $z=-2.27$ and $z=0.36$ is .
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Solution

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Solution Steps

Step 1: Calculate the Area Between \( z = -2.49 \) and \( z = -0.42 \)

To find the area under the standard normal curve between the z-values \( z = -2.49 \) and \( z = -0.42 \), we use the cumulative distribution function \( \Phi \):

\[ P = \Phi(Z_{end}) - \Phi(Z_{start}) = \Phi(-0.42) - \Phi(-2.49) \]

From the calculations, we find:

\[ P = 0.3309 \]

Thus, the area between \( z = -2.49 \) and \( z = -0.42 \) is \( 0.3309 \).

Step 2: Calculate the Area Between \( z = -2.27 \) and \( z = 0.36 \)

Next, we calculate the area under the standard normal curve between the z-values \( z = -2.27 \) and \( z = 0.36 \):

\[ P = \Phi(Z_{end}) - \Phi(Z_{start}) = \Phi(0.36) - \Phi(-2.27) \]

From the calculations, we find:

\[ P = 0.629 \]

Thus, the area between \( z = -2.27 \) and \( z = 0.36 \) is \( 0.629 \).

Final Answer

The areas under the standard normal curve are as follows:

  • The area between \( z = -2.49 \) and \( z = -0.42 \) is \( \boxed{0.3309} \).
  • The area between \( z = -2.27 \) and \( z = 0.36 \) is \( \boxed{0.629} \).
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