Questions: element or compound type of solid formed force holding the solid together melting point of solid ------------ CH3Br ? ? ✓ Os ? ✓ ? Ar ? ✓ ? ? ? ✓

element or compound  type of solid formed  force holding the solid together  melting point of solid
------------
CH3Br  ?  ?  ✓
Os  ?  ✓  ?
Ar  ?  ✓  ?
  ?  ?  ✓
Transcript text: \begin{tabular}{|c|c|c|c|} \hline \begin{tabular}{c} element \\ or \\ compound \end{tabular} & \begin{tabular}{c} type of solid \\ formed \end{tabular} & \begin{tabular}{c} force holding the solid \\ together \end{tabular} & \begin{tabular}{c} melting point \\ of solid \end{tabular} \\ \hline $\mathrm{CH}_{3} \mathrm{Br}$ & $?$ & $?$ & $\checkmark$ \\ \hline Os & $?$ & $\checkmark$ & $?$ \\ \hline Ar & $?$ & $\checkmark$ & $?$ \\ \hline & $?$ & $?$ & $\checkmark$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Determine the Type of Solid for Each Element or Compound
  • CH\(_3\)Br: This is a molecular compound. Molecular compounds typically form molecular solids, which are held together by intermolecular forces such as dipole-dipole interactions, London dispersion forces, and hydrogen bonds (if applicable). In the case of CH\(_3\)Br, the primary force is dipole-dipole interactions due to the polar nature of the molecule.

  • Os (Osmium): Osmium is a metal, and metals form metallic solids. These solids are held together by metallic bonds, which involve a "sea of electrons" that are delocalized over a lattice of metal cations.

  • Ar (Argon): Argon is a noble gas, and noble gases form atomic solids. These are held together by weak London dispersion forces, as they are nonpolar and consist of individual atoms.

Step 2: Identify the Force Holding the Solid Together
  • CH\(_3\)Br: As mentioned, the force holding the solid together is primarily dipole-dipole interactions.

  • Os (Osmium): The force holding the solid together is metallic bonding.

  • Ar (Argon): The force holding the solid together is London dispersion forces.

Step 3: Determine the Melting Point of the Solid
  • CH\(_3\)Br: Molecular solids generally have low melting points compared to ionic or metallic solids. The melting point of CH\(_3\)Br is relatively low due to the weak intermolecular forces.

  • Os (Osmium): Metallic solids typically have high melting points. Osmium, being a transition metal, has a very high melting point.

  • Ar (Argon): Atomic solids formed by noble gases have very low melting points due to weak London dispersion forces.

Final Answer

  • CH\(_3\)Br: Type of solid: Molecular solid; Force: Dipole-dipole interactions; Melting point: Low
  • Os: Type of solid: Metallic solid; Force: Metallic bonding; Melting point: High
  • Ar: Type of solid: Atomic solid; Force: London dispersion forces; Melting point: Low

\[ \begin{array}{|c|c|c|c|} \hline \text{Element or Compound} & \text{Type of Solid} & \text{Force Holding the Solid Together} & \text{Melting Point} \\ \hline \mathrm{CH}_{3} \mathrm{Br} & \text{Molecular} & \text{Dipole-dipole interactions} & \text{Low} \\ \hline \text{Os} & \text{Metallic} & \text{Metallic bonding} & \text{High} \\ \hline \text{Ar} & \text{Atomic} & \text{London dispersion forces} & \text{Low} \\ \hline \end{array} \]

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