Questions: Prove the following limits do not exist by finding both the left-hand and right-hand limit (a) lim (x → 3) ((x^2 + 2x - 3) / (x - 3))

Prove the following limits do not exist by finding both the left-hand and right-hand limit
(a) lim (x → 3) ((x^2 + 2x - 3) / (x - 3))
Transcript text: Prove the following limits do not exist by finding both the left-hand and right-hand lim (a) $\lim _{\substack{x \rightarrow 3}}\left(\frac{x^{2}+2 x-3}{x-3}\right)$
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Solution

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Solution Steps

To determine if the limit exists, we need to evaluate the left-hand limit and the right-hand limit as \( x \) approaches 3. If these two limits are not equal, the limit does not exist.

Step 1: Define the Function

We are given the function: \[ f(x) = \frac{x^2 + 2x - 3}{x - 3} \]

Step 2: Simplify the Function

First, we factor the numerator: \[ x^2 + 2x - 3 = (x - 1)(x + 3) \] Thus, the function becomes: \[ f(x) = \frac{(x - 1)(x + 3)}{x - 3} \]

Step 3: Evaluate the Left-Hand Limit

We evaluate the left-hand limit as \( x \) approaches 3 from the left (\( x \to 3^- \)): \[ \lim_{{x \to 3^-}} \frac{(x - 1)(x + 3)}{x - 3} = -\infty \]

Step 4: Evaluate the Right-Hand Limit

We evaluate the right-hand limit as \( x \) approaches 3 from the right (\( x \to 3^+ \)): \[ \lim_{{x \to 3^+}} \frac{(x - 1)(x + 3)}{x - 3} = \infty \]

Step 5: Compare the Limits

Since the left-hand limit (\( -\infty \)) and the right-hand limit (\( \infty \)) are not equal, the limit does not exist.

Final Answer

\[ \boxed{\text{The limit does not exist.}} \]

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