Questions: Rationalize the denominator of the expression.
[
fracsqrta+sqrtbsqrta-sqrtb
]
Transcript text: Rationalize the denominator of the expression.
\[
\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}}
\]
Solution
Solution Steps
Step 1: Identify the Expression
We start with the expression:
\[
\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}}
\]
Step 2: Multiply by the Conjugate
To rationalize the denominator, we multiply both the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{a} + \sqrt{b}\):
\[
\frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}-\sqrt{b}} \cdot \frac{\sqrt{a}+\sqrt{b}}{\sqrt{a}+\sqrt{b}}
\]
Step 3: Simplify the Expression
After performing the multiplication, we have:
\[
\frac{(\sqrt{a}+\sqrt{b})(\sqrt{a}+\sqrt{b})}{(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})}
\]
Step 4: Factor the Numerator and Denominator
The numerator simplifies to:
\[
(\sqrt{a}+\sqrt{b})^2 = a + 2\sqrt{ab} + b
\]
The denominator simplifies using the difference of squares:
\[
(\sqrt{a})^2 - (\sqrt{b})^2 = a - b
\]
Step 5: Write the Final Expression
Thus, the rationalized expression is:
\[
\frac{a + 2\sqrt{ab} + b}{a - b}
\]