Questions: Given the function g(x)=-x^2+8x+24, determine the average rate of change of the function over the interval 2 ≤ x ≤ 10.
Transcript text: Given the function $g(x)=-x^{2}+8 x+24$, determine the average rate of change of the function over the interval $2 \leq x \leq 10$.
Solution
Solution Steps
Step 1: Identify the function and interval
The given function is \( g(x) = -x^{2} + 8x + 24 \), and the interval over which the average rate of change is to be calculated is \( 2 \leq x \leq 10 \).
Step 2: Calculate \( g(2) \)
Substitute \( x = 2 \) into the function:
\[
g(2) = -(2)^{2} + 8(2) + 24 = -4 + 16 + 24 = 36.
\]
Step 3: Calculate \( g(10) \)
Substitute \( x = 10 \) into the function:
\[
g(10) = -(10)^{2} + 8(10) + 24 = -100 + 80 + 24 = 4.
\]
Step 4: Compute the average rate of change
The average rate of change is given by:
\[
\text{Average rate of change} = \frac{g(10) - g(2)}{10 - 2} = \frac{4 - 36}{8} = \frac{-32}{8} = -4.
\]