Questions: Question 2
10 pts
The critical F value with 8 numerator and 29 denominator degrees of freedom at α=.01 is
3.2
3.33
2.28
3.64
Transcript text: Question 2
10 pts
The critical $F$ value with 8 numerator and 29 denominator degrees of freedom at $\alpha=.01$ is
3.2
3.33
2.28
3.64
Solution
Solution Steps
Step 1: Define the Problem
We need to find the critical \( F \) value for a one-way ANOVA test with \( 8 \) numerator degrees of freedom and \( 29 \) denominator degrees of freedom at a significance level of \( \alpha = 0.01 \).
Step 2: Calculate the Critical F Value
Using the F-distribution, the critical value can be determined using the percent-point function (inverse cumulative distribution function). For our parameters, we calculate:
\[
F_{critical} = F_{0.99}(8, 29)
\]
Step 3: Output the Result
After performing the calculation, we find that the critical \( F \) value is:
\[
F_{critical} \approx 3.20
\]
Final Answer
The critical \( F \) value with \( 8 \) numerator and \( 29 \) denominator degrees of freedom at \( \alpha = 0.01 \) is