Questions: Question 10 of 10 Which of the functions below could have created this graph? A. F(x)=x^4+2x^3+5 B. F(x)=x^7-x^3-3x^2+3 C. F(x)=-x^8-5x^4-4x^2+5 D. F(x)=-x^11+5x^8+4

Transcript text: Question 10 of 10 Which of the functions below could have created this graph? A. $F(x)=x^{4}+2 x^{3}+5$ B. $F(x)=x^{7}-x^{3}-3 x^{2}+3$ C. $F(x)=-x^{8}-5 x^{4}-4 x^{2}+5$ D. $F(x)=-x^{11}+5 x^{8}+4$

Solution

Solution Steps

Step 1: Analyze the graph's end behavior

The graph's ends point in opposite directions, meaning the function has an odd degree. The left end points downward and the right end points upward, indicating a positive leading coefficient.

Step 2: Eliminate options based on end behavior

Options A and C have even degrees, so they can be eliminated. Option D has a negative leading coefficient, which doesn't match the graph, so it can be eliminated. Only option B has an odd degree and a positive leading coefficient.

Final Answer: The answer is B.

Was this solution helpful?

Unhelpful

Helpful

Questions asked by other users

< Previous Next >

Thank you for your feedback.

Copied!