Questions: How many milliliters of the approximately 0.14 M prepared copper(II) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.014 M copper(II) sulfate solution?

Solution Steps

To solve this problem, we need to use the concept of dilution, which is described by the formula:

\[ C_1V_1 = C_2V_2 \]

where:

• \(C_1\) is the concentration of the stock solution,
• \(V_1\) is the volume of the stock solution needed,
• \(C_2\) is the concentration of the diluted solution,
• \(V_2\) is the volume of the diluted solution.

From the problem, we have:

• \(C_1 = 0.14 \, \text{M}\)
• \(C_2 = 0.014 \, \text{M}\)
• \(V_2 = 100.00 \, \text{mL}\)

We need to find \(V_1\), the volume of the stock solution required. Rearrange the dilution formula to solve for \(V_1\):

\[ V_1 = \frac{C_2V_2}{C_1} \]

Substitute the known values into the equation:

\[ V_1 = \frac{0.014 \, \text{M} \times 100.00 \, \text{mL}}{0.14 \, \text{M}} \]

Perform the calculation:

\[ V_1 = \frac{1.4 \, \text{mL}}{0.14} = 10.00 \, \text{mL} \]

Final Answer