Questions: The probability of a company having a section in the newspaper is 0.43, and the probability of a company having a website given that the company has a section in the newspaper is 0.84. What is the probability of a company having a website and a section in the newspaper?
Round your answer to three decimal places.
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QUESTION 5 - 1 POINT
The probability of a company having a section in the newspaper is 0.43 , and the probability of a company having a website given that the company has a section in the newspaper is 0.84 . What is the probability of a company having a website and a section in the newspaper?
Round your answer to three decimal places.
Provide your answer below:
$\square$
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Solution
Solution Steps
To find the probability of a company having both a section in the newspaper and a website, we can use the concept of conditional probability. Specifically, we use the formula for the joint probability of two events: \( P(A \cap B) = P(B|A) \times P(A) \), where \( P(A) \) is the probability of having a section in the newspaper, and \( P(B|A) \) is the probability of having a website given that the company has a section in the newspaper.
Step 1: Define the Probabilities
Let \( P(A) \) be the probability of a company having a section in the newspaper, which is given as:
\[
P(A) = 0.43
\]
Let \( P(B|A) \) be the probability of a company having a website given that it has a section in the newspaper, which is given as:
\[
P(B|A) = 0.84
\]
Step 2: Calculate the Joint Probability
To find the probability of a company having both a section in the newspaper and a website, we use the formula for joint probability:
\[
P(A \cap B) = P(B|A) \times P(A)
\]
Substituting the known values:
\[
P(A \cap B) = 0.84 \times 0.43
\]
Step 3: Compute the Result
Calculating the above expression gives:
\[
P(A \cap B) = 0.3612
\]
Rounding this to three decimal places, we have:
\[
P(A \cap B) \approx 0.361
\]
Final Answer
The probability of a company having a website and a section in the newspaper is \\(\boxed{0.361}\\).