Questions: Which of the following shows sqrt(-16) simplified and written as a complex number?
4+i
-4 i
16 i
0+4 i
Transcript text: Which of the following shows $\sqrt{-16}$ simplified and written as a complex number?
$4+i$
$-4 i$
$16 i$
$0+4 i$
Solution
Solution Steps
To simplify \(\sqrt{-16}\) and express it as a complex number, we need to recognize that the square root of a negative number involves the imaginary unit \(i\), where \(i = \sqrt{-1}\). Therefore, \(\sqrt{-16}\) can be rewritten as \(\sqrt{16} \times \sqrt{-1}\). The square root of 16 is 4, and \(\sqrt{-1}\) is \(i\). Thus, \(\sqrt{-16}\) simplifies to \(4i\).
Step 1: Identify the Expression
We need to simplify the expression \(\sqrt{-16}\). This involves recognizing that we are dealing with a negative number under the square root.
Step 2: Apply the Properties of Square Roots
Using the property of square roots, we can separate the expression as follows:
\[
\sqrt{-16} = \sqrt{16} \times \sqrt{-1}
\]
Step 3: Simplify Each Component
We know that:
\[
\sqrt{16} = 4 \quad \text{and} \quad \sqrt{-1} = i
\]
Thus, we can combine these results:
\[
\sqrt{-16} = 4 \times i = 4i
\]
Final Answer
The simplified form of \(\sqrt{-16}\) as a complex number is \(\boxed{4i}\).