Questions: Which of the following shows sqrt(-16) simplified and written as a complex number? 4+i -4 i 16 i 0+4 i

Which of the following shows sqrt(-16) simplified and written as a complex number?
4+i
-4 i
16 i
0+4 i
Transcript text: Which of the following shows $\sqrt{-16}$ simplified and written as a complex number? $4+i$ $-4 i$ $16 i$ $0+4 i$
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Solution

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Solution Steps

To simplify \(\sqrt{-16}\) and express it as a complex number, we need to recognize that the square root of a negative number involves the imaginary unit \(i\), where \(i = \sqrt{-1}\). Therefore, \(\sqrt{-16}\) can be rewritten as \(\sqrt{16} \times \sqrt{-1}\). The square root of 16 is 4, and \(\sqrt{-1}\) is \(i\). Thus, \(\sqrt{-16}\) simplifies to \(4i\).

Step 1: Identify the Expression

We need to simplify the expression \(\sqrt{-16}\). This involves recognizing that we are dealing with a negative number under the square root.

Step 2: Apply the Properties of Square Roots

Using the property of square roots, we can separate the expression as follows: \[ \sqrt{-16} = \sqrt{16} \times \sqrt{-1} \]

Step 3: Simplify Each Component

We know that: \[ \sqrt{16} = 4 \quad \text{and} \quad \sqrt{-1} = i \] Thus, we can combine these results: \[ \sqrt{-16} = 4 \times i = 4i \]

Final Answer

The simplified form of \(\sqrt{-16}\) as a complex number is \(\boxed{4i}\).

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