Questions: Solve by using the quadratic formula.
6x^2 - 8x = 64
4,-8/3
4,-9/2
14/3,-3
-5 ± i sqrt(479)/6
Transcript text: Solve by using the quadratic formula.
\[
6 x^{2}-8 x=64
\]
$\left\{4,-\frac{8}{3}\right\}$
$\left\{4,-\frac{9}{2}\right\}$
$\left\{\frac{14}{3},-3\right\}$
$\left\{\frac{-5 \pm i \sqrt{479}}{6}\right\}$
Solution
Solution Steps
To solve the quadratic equation \(6x^2 - 8x = 64\) using the quadratic formula, we first need to rewrite the equation in the standard form \(ax^2 + bx + c = 0\). Then, we identify the coefficients \(a\), \(b\), and \(c\) and apply the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Solution Approach
Rewrite the equation in the form \(ax^2 + bx + c = 0\).
Identify the coefficients \(a\), \(b\), and \(c\).
Use the quadratic formula to find the solutions for \(x\).
Step 1: Rewrite the Equation
We start with the equation:
\[
6x^2 - 8x = 64
\]
Rearranging it into standard form gives:
\[
6x^2 - 8x - 64 = 0
\]
Step 2: Identify Coefficients
From the standard form \(ax^2 + bx + c = 0\), we identify the coefficients:
\[
a = 6, \quad b = -8, \quad c = -64
\]
Step 3: Calculate the Discriminant
We calculate the discriminant using the formula \(D = b^2 - 4ac\):
\[
D = (-8)^2 - 4 \cdot 6 \cdot (-64) = 64 + 1536 = 1600
\]
Step 4: Apply the Quadratic Formula
Using the quadratic formula \(x = \frac{-b \pm \sqrt{D}}{2a}\), we find the solutions:
\[
x = \frac{-(-8) \pm \sqrt{1600}}{2 \cdot 6} = \frac{8 \pm 40}{12}
\]
Calculating the two possible values:
For the positive root:
\[
x_1 = \frac{8 + 40}{12} = \frac{48}{12} = 4
\]
For the negative root:
\[
x_2 = \frac{8 - 40}{12} = \frac{-32}{12} = -\frac{8}{3}
\]
Final Answer
The solutions to the equation are:
\[
\boxed{x = 4} \quad \text{and} \quad \boxed{x = -\frac{8}{3}}
\]