Questions: Complete the table below. (hatp) (hatmathbfq=mathbf1-hatmathbfp) (hatmathbfp q) --- --- --- 0.6 0.7 0.8 0.9 1.0 (Type integers or decimals.)

Complete the table below.

 (hatp)  (hatmathbfq=mathbf1-hatmathbfp)  (hatmathbfp q) 
 ---  ---  --- 
 0.6     
 0.7     
 0.8     
 0.9     
 1.0     

(Type integers or decimals.)
Transcript text: Complete the table below. \begin{tabular}{|c|c|c|} \hline$\hat{p}$ & $\hat{\mathbf{q}}=\mathbf{1}-\hat{\mathbf{p}}$ & $\hat{\mathbf{p q}}$ \\ \hline 0.6 & $\square$ & $\square$ \\ \hline 0.7 & $\square$ & $\square$ \\ \hline 0.8 & $\square$ & $\square$ \\ \hline 0.9 & $\square$ & $\square$ \\ \hline 1.0 & $\square$ & $\square$ \\ \hline \end{tabular} (Type integers or decimals.)
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Solution

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Solution Steps

To complete the table, we need to calculate two values for each given \(\hat{p}\):

  1. \(\hat{\mathbf{q}} = 1 - \hat{\mathbf{p}}\)
  2. \(\hat{\mathbf{p q}} = \hat{\mathbf{p}} \times \hat{\mathbf{q}}\)

We will iterate through the given \(\hat{p}\) values, compute \(\hat{\mathbf{q}}\) and \(\hat{\mathbf{p q}}\), and then fill in the table.

Step 1: Calculate \(\hat{\mathbf{q}}\)

For each value of \(\hat{p}\), we compute \(\hat{\mathbf{q}} = 1 - \hat{\mathbf{p}}\):

  • For \(\hat{p} = 0.6\): \[ \hat{\mathbf{q}} = 1 - 0.6 = 0.4 \]
  • For \(\hat{p} = 0.7\): \[ \hat{\mathbf{q}} = 1 - 0.7 = 0.3 \]
  • For \(\hat{p} = 0.8\): \[ \hat{\mathbf{q}} = 1 - 0.8 = 0.2 \]
  • For \(\hat{p} = 0.9\): \[ \hat{\mathbf{q}} = 1 - 0.9 = 0.1 \]
  • For \(\hat{p} = 1.0\): \[ \hat{\mathbf{q}} = 1 - 1.0 = 0.0 \]
Step 2: Calculate \(\hat{\mathbf{p q}}\)

Next, we compute \(\hat{\mathbf{p q}} = \hat{\mathbf{p}} \times \hat{\mathbf{q}}\):

  • For \(\hat{p} = 0.6\): \[ \hat{\mathbf{p q}} = 0.6 \times 0.4 = 0.24 \]
  • For \(\hat{p} = 0.7\): \[ \hat{\mathbf{p q}} = 0.7 \times 0.3 = 0.21 \]
  • For \(\hat{p} = 0.8\): \[ \hat{\mathbf{p q}} = 0.8 \times 0.2 = 0.16 \]
  • For \(\hat{p} = 0.9\): \[ \hat{\mathbf{p q}} = 0.9 \times 0.1 = 0.09 \]
  • For \(\hat{p} = 1.0\): \[ \hat{\mathbf{p q}} = 1.0 \times 0.0 = 0.0 \]

Final Answer

The completed table is as follows:

\[ \begin{array}{|c|c|c|} \hline \hat{p} & \hat{\mathbf{q}} & \hat{\mathbf{p q}} \\ \hline 0.6 & 0.4 & 0.24 \\ 0.7 & 0.3 & 0.21 \\ 0.8 & 0.2 & 0.16 \\ 0.9 & 0.1 & 0.09 \\ 1.0 & 0.0 & 0.0 \\ \hline \end{array} \]

Thus, the values are:

  • For \(\hat{p} = 0.6\): \(\hat{\mathbf{q}} = 0.4\), \(\hat{\mathbf{p q}} = 0.24\)
  • For \(\hat{p} = 0.7\): \(\hat{\mathbf{q}} = 0.3\), \(\hat{\mathbf{p q}} = 0.21\)
  • For \(\hat{p} = 0.8\): \(\hat{\mathbf{q}} = 0.2\), \(\hat{\mathbf{p q}} = 0.16\)

The final answer is: \[ \boxed{ \begin{array}{|c|c|c|} \hline \hat{p} & \hat{\mathbf{q}} & \hat{\mathbf{p q}} \\ \hline 0.6 & 0.4 & 0.24 \\ 0.7 & 0.3 & 0.21 \\ 0.8 & 0.2 & 0.16 \\ \hline \end{array} } \]

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