We start by converting the numbers from base 5 to base 10. The number \(230_5\) is calculated as follows:
\[ 230_5 = 2 \cdot 5^2 + 3 \cdot 5^1 + 0 \cdot 5^0 = 2 \cdot 25 + 3 \cdot 5 + 0 = 50 + 15 + 0 = 65 \]
The number \(3_5\) is simply:
\[ 3_5 = 3 \cdot 5^0 = 3 \]
Next, we perform the division of the two base 10 numbers:
\[ \frac{65}{3} = 21 \quad \text{with a remainder of} \quad 2 \]
Now, we convert the quotient \(21\) and the remainder \(2\) back to base 5.
For the quotient \(21\):
\[ 21_{10} = 4 \cdot 5^1 + 1 \cdot 5^0 = 41_5 \]
For the remainder \(2\):
\[ 2_{10} = 2 \cdot 5^0 = 2_5 \]
The quotient is \(41_5\) and the remainder is \(2_5\). Thus, the final answer is:
\[ \boxed{41_5 \text{ R } 2_5} \]
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