Questions: Graph the system below and write its solution.
y=3x-2
x+2y=3
Transcript text: Graph the system below and write its solution.
\[
\left\{\begin{array}{l}
y=3 x-2 \\
x+2 y=3
\end{array}\right.
\]
Note that you can also answer "No solution" or "Infinitely many
Explanation
Check
Solution
Solution Steps
Step 1: Write the system of equations
The given system of equations is:
\[
\begin{cases}
y = 3x - 2 \\
x + 2y = 3
\end{cases}
\]
Step 2: Graph the first equation
The first equation is \( y = 3x - 2 \). This is a linear equation in slope-intercept form \( y = mx + b \), where \( m = 3 \) (slope) and \( b = -2 \) (y-intercept).
Plot the y-intercept \((0, -2)\) on the graph.
Use the slope to find another point. From \((0, -2)\), move up 3 units and right 1 unit to get the point \((1, 1)\).
Draw the line through these points.
Step 3: Graph the second equation
The second equation is \( x + 2y = 3 \). Rewrite it in slope-intercept form \( y = mx + b \).
Solve for \( y \):
\[ 2y = -x + 3 \]
\[ y = -\frac{1}{2}x + \frac{3}{2} \]
Plot the y-intercept \((0, \frac{3}{2})\) on the graph.
Use the slope to find another point. From \((0, \frac{3}{2})\), move down 1 unit and right 2 units to get the point \((2, 0.5)\).
Draw the line through these points.
Step 4: Find the intersection point
The solution to the system of equations is the point where the two lines intersect.
Set the equations equal to each other to find the x-coordinate of the intersection:
\[ 3x - 2 = -\frac{1}{2}x + \frac{3}{2} \]
Solve for \( x \):
\[ 3x + \frac{1}{2}x = \frac{3}{2} + 2 \]
\[ \frac{7}{2}x = \frac{7}{2} \]
\[ x = 1 \]
Substitute \( x = 1 \) back into the first equation to find the y-coordinate:
\[ y = 3(1) - 2 \]
\[ y = 1 \]
Final Answer
The solution to the system of equations is the point \((1, 1)\).