Questions: What is the oxidation number of bromine as a reactant and in the product?

Transcript text: What is the oxidation number of bromine as a reactant and in the product?

Solution

Solution Steps

Step 1: Determine the oxidation number of bromine in Br\(_2\)

In diatomic molecules like Br\(_2\), each bromine atom has an oxidation number of 0 because they are in their elemental form.

Step 2: Determine the oxidation number of bromine in Al\(_2\)Br\(_6\)

In the compound Al\(_2\)Br\(_6\), aluminum typically has an oxidation number of +3. To find the oxidation number of bromine, we set up the following equation based on the sum of oxidation numbers in a neutral compound being zero:

\[ 2(\text{oxidation number of Al}) + 6(\text{oxidation number of Br}) = 0 \]

Substituting the known oxidation number of aluminum:

\[ 2(+3) + 6(\text{oxidation number of Br}) = 0 \]

Solving for the oxidation number of bromine:

\[ 6(\text{oxidation number of Br}) = -6 \]

\[ \text{oxidation number of Br} = -1 \]

Final Answer

The oxidation number of bromine as a reactant in Br\(_2\) is \(\boxed{0}\).

The oxidation number of bromine in the product Al\(_2\)Br\(_6\) is \(\boxed{-1}\).

Was this solution helpful?

Unhelpful

Helpful

Questions asked by other users

< Previous Next >