Questions: Derive the amino acid sequence that is coded by this mRNA sequence. Use three-letter amino acid codes in your answer. 5' CAA GAG GUA UCC UAC AGA 3'

Derive the amino acid sequence that is coded by this mRNA sequence. Use three-letter amino acid codes in your answer. 5' CAA GAG GUA UCC UAC AGA 3'
Transcript text: Derive the amino acid sequence that is coded by this mRNA sequence. Use three-letter amino acid codes in your answer. $5^{\prime}$ CAA GAG GUA UCC UAC AGA 3'
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Solution

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Solution Steps

Step 1: Divide the mRNA sequence into codons

The mRNA sequence is read in groups of three nucleotides called codons. The given sequence is:

5' CAA GAG GUA UCC UAC AGA 3'

Divide it into codons:

CAA | GAG | GUA | UCC | UAC | AGA

Step 2: Translate each codon into its corresponding amino acid

Using the genetic code table, we can find the amino acid corresponding to each codon:

  • CAA: Gln (Glutamine)
  • GAG: Glu (Glutamic acid)
  • GUA: Val (Valine)
  • UCC: Ser (Serine)
  • UAC: Tyr (Tyrosine)
  • AGA: Arg (Arginine)
Step 3: Combine the amino acids to form the sequence

Combining the amino acids in the order derived from the mRNA sequence gives us the final amino acid sequence.

Final Answer

\\(\boxed{\text{Gln-Glu-Val-Ser-Tyr-Arg}}\\)

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