Questions: Graphing a line by first finding its slope and y-intercept
The equation of a line is given below.
-6x-2y=-8
Find the slope and the y-intercept.
Then use them to graph the line.
slope:
y-intercept:
Transcript text: Graphing a line by first finding its slope and y-intercept
The equation of a line is given below.
\[
-6 x-2 y=-8
\]
Find the slope and the $y$-intercept.
Then use them to graph the line.
slope: $\square$
$y$-intercept: $\square$
Solution
Solution Steps
Step 1: Rewrite the equation in slope-intercept form
The slope-intercept form of a linear equation is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.
We are given the equation $-6x - 2y = -8$. To rewrite this equation in slope-intercept form, we need to isolate $y$.
First, add $6x$ to both sides of the equation:
$-2y = 6x - 8$
Next, divide both sides by $-2$:
$y = \frac{6x - 8}{-2}$
$y = -3x + 4$
Step 2: Identify the slope and y-intercept
Now that the equation is in slope-intercept form ($y = mx + b$), we can identify the slope and y-intercept.
The slope $m$ is the coefficient of $x$, which is $-3$.
The y-intercept $b$ is the constant term, which is $4$.
Step 3: Graph the line
To graph the line, we start by plotting the y-intercept, which is the point $(0, 4)$.
From the y-intercept, we use the slope to find another point on the line. The slope is $-3$, which can be written as $\frac{-3}{1}$. This means that for every 1 unit we move to the right along the x-axis, we move 3 units down along the y-axis.
So, starting at $(0, 4)$, we move 1 unit to the right and 3 units down to find the point $(1, 1)$.
Plot the point $(1, 1)$.
Draw a line through the points $(0, 4)$ and $(1, 1)$.