Questions: Calculate the pH of each solution at 2 J°C. 1.0 x 10^-3 M HCl pH= 3.0000 0.1 M HNO3 pH= 1.0000 1.0 x 10^-3 M NaOH pH= 11.0000 0.01 M KOH pH=
Transcript text: Calculate the pH of each solution at $2 \mathrm{~J}^{\circ} \mathrm{C}$.
$1.0 \times 10^{-3} \mathrm{M} \mathrm{HCl} \quad \mathrm{pH}=$
3.0000
$0.1 \mathrm{M} \mathrm{HNO}_{3} \quad \mathrm{pH}=$
1.0000
$1.0 \times 10^{-3} \mathrm{M} \mathrm{NaOH}$
$\mathrm{pH}=$
11.0000
0.01 M KOH
$\mathrm{pH}=$
Solution
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