Questions: When a solution of KOH is neutralized by hydrochloric acid, the solution gets hot. Calculate the change in heat of the solution (in J). Mass of combined solution 205 g Temperature change of the solution = 5.50 K Specific heat capacity of the solution = 4.18 J / g ⋅ K Give your answer to three significant figures.

When a solution of KOH is neutralized by hydrochloric acid, the solution gets hot. Calculate the change in heat of the solution (in J). Mass of combined solution 205 g Temperature change of the solution = 5.50 K Specific heat capacity of the solution = 4.18 J / g ⋅ K Give your answer to three significant figures.
Transcript text: When a solution of KOH is neutralized by hydrochloric acid, the solution gets hot. Calculate the change in heat of the solution (in J). Mass of combined solution $\mathbf{2 0 5} \mathrm{g}$ Temperature change of the solution $=\mathbf{5 . 5 0} \mathrm{K}$ Specific heat capacity of the solution $=4.18 \mathrm{~J} / \mathrm{g} \cdot \mathrm{K}$ Give your answer to three significant figures. $\square$ Submit Answer Try Another Version 3 item attempts remaining
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Solution

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Solution Steps

Step 1: Identify the Given Values

We are given the following values:

  • Mass of the solution, \( m = 205 \, \text{g} \)
  • Temperature change, \( \Delta T = 5.50 \, \text{K} \)
  • Specific heat capacity, \( c = 4.18 \, \text{J/g} \cdot \text{K} \)
Step 2: Use the Formula for Heat Change

The formula to calculate the change in heat (\( q \)) is: \[ q = m \cdot c \cdot \Delta T \]

Step 3: Substitute the Values into the Formula

Substitute the given values into the formula: \[ q = 205 \, \text{g} \times 4.18 \, \text{J/g} \cdot \text{K} \times 5.50 \, \text{K} \]

Step 4: Calculate the Heat Change

Perform the multiplication: \[ q = 205 \times 4.18 \times 5.50 = 4719.95 \, \text{J} \]

Step 5: Round to Three Significant Figures

Round the result to three significant figures: \[ q \approx 4720 \, \text{J} \]

Final Answer

The change in heat of the solution is \(\boxed{4720 \, \text{J}}\).

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