Questions: Problem Set C 18 Given: triangle ABC ~ triangle DEF, m angle A=50, m angle D=2x+5y m angle F=5x+y, m angle B=102-x Find: m angle F

Problem Set C
18 Given: triangle ABC ~ triangle DEF,
m angle A=50, m angle D=2x+5y
m angle F=5x+y, m angle B=102-x

Find: m angle F
Transcript text: Problem Set C 18 Given: $\triangle \mathrm{ABC} \sim \triangle \mathrm{DEF}$, \[ \begin{array}{l} \mathrm{m} \angle \mathrm{~A}=50, \mathrm{~m} \angle \mathrm{D}=2 \mathrm{x}+5 \mathrm{y} \\ \mathrm{~m} \angle \mathrm{~F}=5 \mathrm{x}+\mathrm{y}, \mathrm{~m} \angle \mathrm{~B}=102-\mathrm{x} \end{array} \] Find: $m \angle F$
failed

Solution

failed
failed

Solution Steps

Step 1: Establish relationships between angles

Since ΔABC ~ ΔDEF, corresponding angles are congruent. Thus, m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F.

Step 2: Set up equations

We are given m∠A = 50, m∠D = 2x + 5y, m∠F = 5x + y, and m∠B = 102 - x. Since m∠A = m∠D, we have 50 = 2x + 5y. The sum of angles in a triangle is 180 degrees. In ΔABC, m∠A + m∠B + m∠C = 180, so 50 + (102 - x) + m∠C = 180, which simplifies to m∠C = 28 + x. Similarly, in ΔDEF, m∠D + m∠E + m∠F = 180. Since m∠B = m∠E, we have (2x + 5y) + (102 - x) + (5x + y) = 180, which simplifies to 6x + 6y + 102 = 180, or x + y = 13.

Step 3: Solve for x and y and find m∠F

We have the system of equations: 2x + 5y = 50 x + y = 13 Multiplying the second equation by 2 gives 2x + 2y = 26. Subtracting this from the first equation gives 3y = 24, so y = 8. Substituting y = 8 into x + y = 13 gives x + 8 = 13, so x = 5. Now we can find m∠F = 5x + y = 5(5) + 8 = 25 + 8 = 33.

Final Answer

m∠F = 33°

Was this solution helpful?
failed
Unhelpful
failed
Helpful