Questions: 9-3 ÷ (1/3) + 1 = ?

9-3 ÷ (1/3) + 1 = ?
Transcript text: $9-3 \div \frac{1}{3}+1=?$
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Solution

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Solve the expression \(9 - 3 \div \frac{1}{3} + 1\).

Step 1: Handle the division operation.

First, solve \(3 \div \frac{1}{3}\). Dividing by \(\frac{1}{3}\) is the same as multiplying by 3. So, \(3 \div \frac{1}{3} = 3 \times 3 = 9\).

Step 2: Substitute the result back into the expression.

Now, substitute the result of the division into the original expression: \(9 - 9 + 1\).

Step 3: Perform the subtraction and addition.

Subtract 9 from 9: \(9 - 9 = 0\). Then add 1: \(0 + 1 = 1\).

The final result is \(\boxed{1}\).

The solution to the expression \(9 - 3 \div \frac{1}{3} + 1\) is \(\boxed{1}\).

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