Questions: Question 6 (1 point) - Potassium Chloride 15% - Cherry Syrup q.s. ad 390 mL - Sig: 1 tablespoonful b.i.d. How many milliequivalents of potassium chloride (rounded to the nearest whole number) are represented in each prescribed dose? MW of potassium chloride is 74.5 g

Question 6 (1 point) - Potassium Chloride 15% - Cherry Syrup q.s. ad 390 mL - Sig: 1 tablespoonful b.i.d. How many milliequivalents of potassium chloride (rounded to the nearest whole number) are represented in each prescribed dose? MW of potassium chloride is 74.5 g
Transcript text: Question 6 (1 point) - Potassium Chloride $15 \%$ - Cherry Syrup q.s. ad 390 mL - Sig: 1 tablespoonful b.i.d. How many milliequivalents of potassium chloride (rounded to the nartest whole number) are represented in each prescribed dose? MW of potassium chloride is 74.5 g Your Answer: $\square$ Answer units
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Solution

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Solution Steps

Step 1: Determine the concentration of potassium chloride in the solution

The solution is given as a 15% potassium chloride (KCl) solution. This means there are 15 grams of KCl in every 100 mL of solution.

Step 2: Calculate the amount of KCl in the prescribed dose

The prescribed dose is 1 tablespoonful, which is equivalent to 15 mL. To find the amount of KCl in this dose, we use the concentration:

\[ \text{Amount of KCl in 15 mL} = \left(\frac{15 \, \text{g}}{100 \, \text{mL}}\right) \times 15 \, \text{mL} = 2.25 \, \text{g} \]

Step 3: Convert grams of KCl to milliequivalents

The molecular weight (MW) of KCl is 74.5 g/mol. The number of milliequivalents (mEq) is calculated using the formula:

\[ \text{mEq} = \left(\frac{\text{grams of KCl}}{\text{MW of KCl}}\right) \times 1000 \]

Substituting the values:

\[ \text{mEq} = \left(\frac{2.25 \, \text{g}}{74.5 \, \text{g/mol}}\right) \times 1000 \approx 30.2013 \]

Step 4: Round to the nearest whole number

Rounding 30.2013 to the nearest whole number gives 30.

Final Answer

\[ \boxed{30 \, \text{mEq}} \]

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