Questions: Part A How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit

Part A How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit
Transcript text: Part A How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit
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Solution

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Solution Steps

Step 1: Write the Balanced Chemical Equation

The reaction between carbon dioxide (\(\text{CO}_2\)) and hydrogen gas (\(\text{H}_2\)) to produce methane (\(\text{CH}_4\)) and water (\(\text{H}_2\text{O}\)) is represented by the following balanced chemical equation:

\[ \text{CO}_2 + 4\text{H}_2 \rightarrow \text{CH}_4 + 2\text{H}_2\text{O} \]

Step 2: Determine the Mole Ratio

From the balanced equation, we can see that 1 mole of \(\text{CO}_2\) produces 1 mole of \(\text{CH}_4\). Therefore, the mole ratio of \(\text{CO}_2\) to \(\text{CH}_4\) is 1:1.

Step 3: Calculate the Moles of Methane Produced

Given that 59.6 moles of \(\text{CO}_2\) are reacting, and using the 1:1 mole ratio, the moles of methane (\(\text{CH}_4\)) produced will also be 59.6 moles.

Final Answer

The number of moles of methane produced is \(\boxed{59.6 \, \text{moles}}\).

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