Questions: Assume the left beaker contains 4 mM NaCl, 9 mM glucose, and 10 mM albumin. The right beaker contains 10 mM NaCl, 10 mM glucose, and 40 mM albumin. Furthermore, the dialysis membrane is permeable to all substances except albumin. State whether the substances will move (a) to the right beaker, (b) to the left beaker, or (c) not move. Glucose [Choose] Water [Choose] Albumin [Choose] NaCl [Choose]

Assume the left beaker contains 4 mM NaCl, 9 mM glucose, and 10 mM albumin. The right beaker contains 10 mM NaCl, 10 mM glucose, and 40 mM albumin. Furthermore, the dialysis membrane is permeable to all substances except albumin. State whether the substances will move (a) to the right beaker, (b) to the left beaker, or (c) not move.

Glucose
[Choose]

Water
[Choose]

Albumin
[Choose]

NaCl
[Choose]
Transcript text: Assume the left beaker contains $4 \mathrm{mM} \mathrm{NaCl}, 9 \mathrm{mM}$ glucose, and 10 mM albumin. The right beaker contains $10 \mathrm{mM} \mathrm{NaCl}, 10 \mathrm{mM}$ glucose, and 40 mM albumin. Furthermore, the dialysis membrane is permeable to all substances except albumin. State whether the substances will move (a) to the right beaker, (b) to the left beaker, or (c) not move. Glucose [Choose] Water [Choose] Albumin [Choose ] NaCl [Choose]
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Solution

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To answer the question regarding the movement of substances between the two beakers separated by a dialysis membrane, we need to consider the concentration gradients and the permeability of the membrane.

  1. Glucose:

    • The left beaker contains 9 mM glucose, and the right beaker contains 10 mM glucose.
    • Since the membrane is permeable to glucose and there is a concentration gradient (higher concentration in the right beaker), glucose will move from the right beaker to the left beaker to reach equilibrium.
    • Answer: (b) to the left beaker
  2. Water:

    • Water movement is determined by osmotic pressure, which is influenced by the total solute concentration on each side of the membrane.
    • The left beaker has a total solute concentration of 4 mM NaCl + 9 mM glucose = 13 mM (ignoring albumin as it cannot pass through the membrane).
    • The right beaker has a total solute concentration of 10 mM NaCl + 10 mM glucose = 20 mM.
    • Water will move from the left beaker (lower solute concentration) to the right beaker (higher solute concentration) to balance the osmotic pressure.
    • Answer: (a) to the right beaker
  3. Albumin:

    • The membrane is not permeable to albumin, so albumin cannot move between the beakers.
    • Answer: (c) not move
  4. NaCl:

    • The left beaker contains 4 mM NaCl, and the right beaker contains 10 mM NaCl.
    • Since the membrane is permeable to NaCl and there is a concentration gradient (higher concentration in the right beaker), NaCl will move from the right beaker to the left beaker to reach equilibrium.
    • Answer: (b) to the left beaker

In summary:

  • Glucose will move to the left beaker.
  • Water will move to the right beaker.
  • Albumin will not move.
  • NaCl will move to the left beaker.
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