Questions: Marathon Winners The data show the times of a random sample of local marathon runners in hours. Find the range, variance, and standard deviation for the data. Use a TI-83 Plus/TI-84 Plus calculator. 3.3, 2.3, 2.6, 2.4, 2.5, 2.6 Send data to Excel

Marathon Winners The data show the times of a random sample of local marathon runners in hours. Find the range, variance, and standard deviation for the data. Use a TI-83 Plus/TI-84 Plus calculator.
3.3, 2.3, 2.6, 2.4, 2.5, 2.6
Send data to Excel
Transcript text: Marathon Winners The data show the times of a random sample of local marathon runners in hours. Find the range, variance, and standard deviation for the data. Use a TI-83 Plus/TI-84 Plus calculator. \[ \begin{array}{llllll} 3.3 & 2.3 & 2.6 & 2.4 & 2.5 & 2.6 \end{array} \] Send data to Excel
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Solution

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Solution Steps

To find the range, variance, and standard deviation of the given data set, we will follow these steps:

  1. Range: Calculate the difference between the maximum and minimum values in the data set.
  2. Variance: Compute the average of the squared differences from the mean of the data set.
  3. Standard Deviation: Take the square root of the variance to find the standard deviation.
Step 1: Calculate the Range

The range of a data set is the difference between the maximum and minimum values. For the given data set \([3.3, 2.3, 2.6, 2.4, 2.5, 2.6]\), the maximum value is \(3.3\) and the minimum value is \(2.3\).

\[ \text{Range} = 3.3 - 2.3 = 1.0 \]

Step 2: Calculate the Variance

Variance is the average of the squared differences from the mean. First, calculate the mean \(\mu\) of the data set:

\[ \mu = \frac{3.3 + 2.3 + 2.6 + 2.4 + 2.5 + 2.6}{6} = \frac{15.7}{6} \approx 2.6167 \]

Next, calculate the squared differences from the mean and their average:

\[ \text{Variance} = \frac{(3.3 - 2.6167)^2 + (2.3 - 2.6167)^2 + (2.6 - 2.6167)^2 + (2.4 - 2.6167)^2 + (2.5 - 2.6167)^2 + (2.6 - 2.6167)^2}{6} \approx 0.1047 \]

Step 3: Calculate the Standard Deviation

The standard deviation is the square root of the variance:

\[ \text{Standard Deviation} = \sqrt{0.1047} \approx 0.3236 \]

Final Answer

  • Range: \(\boxed{1.0}\)
  • Variance: \(\boxed{0.1047}\)
  • Standard Deviation: \(\boxed{0.3236}\)
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