Questions: Test the claim about the difference between two population means μ1 and μ2 at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed. Claim: μ1=μ2 ; α=0.05. Assume σ1^2=σ2^2 Sample statistics: x̄1=32.3, s1=3.6, n1=14 and x̄2=34.6, s2=2.3, n2=18 Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: μ1 ≥ μ2 B. H0: μ1=μ2 Ha: μ1<μ2 Ha: μ1 ≠ μ2 C. H0: μ1>μ2 D. H0: μ1 ≠ μ2 Ha: μ1 ≤ μ2 Ha: μ1=μ2 E. H0: μ1 ≤ μ2 F. H0: μ1<μ2 Ha: μ1>μ2

Test the claim about the difference between two population means μ1 and μ2 at the level of significance α. Assume the samples are random and independent, and the populations are normally distributed.

Claim: μ1=μ2 ; α=0.05. Assume σ1^2=σ2^2 Sample statistics: x̄1=32.3, s1=3.6, n1=14 and x̄2=34.6, s2=2.3, n2=18

Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: μ1 ≥ μ2 B. H0: μ1=μ2 Ha: μ1<μ2 Ha: μ1 ≠ μ2 C. H0: μ1>μ2 D. H0: μ1 ≠ μ2 Ha: μ1 ≤ μ2 Ha: μ1=μ2 E. H0: μ1 ≤ μ2 F. H0: μ1<μ2 Ha: μ1>μ2
Transcript text: Test the claim about the difference between two population means $\mu_{1}$ and $\mu_{2}$ at the level of significance $\alpha$. Assume the samples are random and independent, and the populations are normally distributed. Claim: $\mu_{1}=\mu_{2} ; \alpha=0.05$. Assume $\sigma_{1}^{2}=\sigma_{2}^{2}$ Sample statistics: $\bar{x}_{1}=32.3, s_{1}=3.6, n_{1}=14$ and \[ \bar{x}_{2}=34.6, s_{2}=2.3, n_{2}=18 \] Identify the null and alternative hypotheses. Choose the correct answer below. A. $\mathrm{H}_{0}: \mu_{1} \geq \mu_{2}$ B. $H_{0}: \mu_{1}=\mu_{2}$ $\mathrm{H}_{\mathrm{a}}: \mu_{1}<\mu_{2}$ $\mathrm{H}_{\mathrm{a}}: \mu_{1} \neq \mu_{2}$ C. $\mathrm{H}_{0}: \mu_{1}>\mu_{2}$ D. $H_{0}: \mu_{1} \neq \mu_{2}$ $H_{a}: \mu_{1} \leq \mu_{2}$ $H_{a}: \mu_{1}=\mu_{2}$ E. $H_{0}: \mu_{1} \leq \mu_{2}$ F. $H_{0}: \mu_{1}<\mu_{2}$ $\mathrm{H}_{\mathrm{a}}: \mu_{1}>\mu_{2}$
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Solution

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Solution Steps

Step 1: Define the Hypotheses

We are testing the claim about the difference between two population means \( \mu_1 \) and \( \mu_2 \). The null and alternative hypotheses are defined as follows:

\[ H_0: \mu_1 = \mu_2 \] \[ H_a: \mu_1 \neq \mu_2 \]

Step 2: Calculate the Standard Error

The standard error (SE) is calculated using the pooled variance \( s_p^2 \):

\[ SE = \sqrt{s_p^2 \left(\frac{1}{n_1} + \frac{1}{n_2}\right)} = 0.0 \]

Step 3: Calculate the Test Statistic

The test statistic \( t \) is calculated using the formula:

\[ t = \frac{\bar{x}_1 - \bar{x}_2}{SE} = \frac{32.3 - 34.6}{0.0} = -1329717924264881.2 \]

Step 4: Calculate the Degrees of Freedom

The degrees of freedom \( df \) for the test is given by:

\[ df = n_1 + n_2 - 2 = 14 + 18 - 2 = 30 \]

Step 5: Calculate the P-value

The P-value is calculated as follows:

\[ P = 2(1 - T(|t|)) = 2(1 - T(1329717924264881.2)) = 0.0 \]

Step 6: Determine the Critical Value

The critical value for a two-tailed test at the significance level \( \alpha = 0.05 \) with \( df = 30 \) is:

\[ \text{Critical Value} = 2.0423 \]

Step 7: Conclusion

Since the P-value \( 0.0 \) is less than the significance level \( \alpha = 0.05 \), we reject the null hypothesis \( H_0 \). This indicates that there is significant evidence to suggest that the means of the two populations are different.

Final Answer

The answer is \( \boxed{B} \).

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