Questions: Set C and the universal set U are defined as follows.
U=1,2,3,4,5,6,7
C=2,4,7
Find the following sets.
Write your answer in roster form or as varnothing.
(a) C^prime cap U= square
(b) C cup varnothing= square
Transcript text: Set $C$ and the universal set $U$ are defined as follows.
\[
\begin{array}{l}
U=\{1,2,3,4,5,6,7\} \\
C=\{2,4,7\}
\end{array}
\]
Find the following sets.
Write your answer in roster form or as $\varnothing$.
(a) $C^{\prime} \cap U=$ $\square$
(b) $C \cup \varnothing=$ $\square$
Solution
Solution Steps
To solve the given problems, we need to understand the concepts of set operations such as complement, intersection, and union.
(a) The complement of set \( C \) with respect to the universal set \( U \) is the set of elements in \( U \) that are not in \( C \). The intersection of this complement with \( U \) will simply be the complement itself since it is already a subset of \( U \).
(b) The union of any set with the empty set \( \varnothing \) is the set itself.
Step 1: Define the Universal Set \( U \) and Set \( C \)
Given:
\[
U = \{1, 2, 3, 4, 5, 6, 7\}
\]
\[
C = \{2, 4, 7\}
\]
Step 2: Find the Complement of \( C \) with Respect to \( U \)
The complement of \( C \) with respect to \( U \) is the set of elements in \( U \) that are not in \( C \):
\[
C' = U \setminus C = \{1, 3, 5, 6\}
\]
Step 3: Find \( C' \cap U \)
Since \( C' \) is already a subset of \( U \), the intersection of \( C' \) with \( U \) is simply \( C' \):
\[
C' \cap U = \{1, 3, 5, 6\}
\]
Step 4: Find \( C \cup \varnothing \)
The union of any set with the empty set \( \varnothing \) is the set itself:
\[
C \cup \varnothing = C = \{2, 4, 7\}
\]
Final Answer
(a) \( C' \cap U = \boxed{\{1, 3, 5, 6\}} \)
(b) \( C \cup \varnothing = \boxed{\{2, 4, 7\}} \)