Questions: Write a balanced overall reaction from these unbalanced half-reactions. - Sn → Sn^2+ Ag^+ → Ag balanced overall reaction:

Transcript text: Write a balanced overall reaction from these unbalanced half-reactions. - $\mathrm{Sn} \longrightarrow \mathrm{Sn}^{2+}$ \[ \mathrm{Ag}^{+} \longrightarrow \mathrm{Ag} \] balanced overall reaction: $\square$

Solution

Solution Steps

Step 1: Identify the Oxidation and Reduction Half-Reactions

The given half-reactions are:

Oxidation: $\mathrm{Sn} \longrightarrow \mathrm{Sn}^{2+}$
Reduction: $\mathrm{Ag}^{+} \longrightarrow \mathrm{Ag}$

Step 2: Balance the Electrons in Each Half-Reaction

For the oxidation half-reaction: \[ \mathrm{Sn} \longrightarrow \mathrm{Sn}^{2+} + 2e^- \]

For the reduction half-reaction: \[ \mathrm{Ag}^{+} + e^- \longrightarrow \mathrm{Ag} \]

Step 3: Equalize the Number of Electrons Transferred

To balance the electrons, multiply the reduction half-reaction by 2: \[ 2(\mathrm{Ag}^{+} + e^- \longrightarrow \mathrm{Ag}) \Rightarrow 2\mathrm{Ag}^{+} + 2e^- \longrightarrow 2\mathrm{Ag} \]

Step 4: Combine the Half-Reactions

Add the balanced half-reactions together: \[ \mathrm{Sn} + 2\mathrm{Ag}^{+} \longrightarrow \mathrm{Sn}^{2+} + 2\mathrm{Ag} \]