Questions: Assign an oxidation number for each element/compound
Na
K+
S3
a) +1
b) 0
c) -1
d) -2
Transcript text: Assign an oxidation number for each element/compound
Na
$\mathrm{K}^{+}$
$\mathrm{S}_{3}$
a) +1
b) 0
c) -1
d) -2
Solution
Solution Steps
Step 1: Assign Oxidation Number to Sodium (Na)
Sodium (Na) is an element in its elemental state. According to the rule that the oxidation number of an element in its elemental state is 0, the oxidation number of Na is 0.
Step 2: Assign Oxidation Number to Potassium Ion (\(\mathrm{K}^{+}\))
The potassium ion (\(\mathrm{K}^{+}\)) is a monatomic ion. The oxidation number of a monatomic ion is equal to its charge. Therefore, the oxidation number of \(\mathrm{K}^{+}\) is +1.
Step 3: Assign Oxidation Number to Sulfur in \(\mathrm{S}_{3}\)
The compound \(\mathrm{S}_{3}\) is a molecule consisting of sulfur atoms. In elemental form, the oxidation number of sulfur is 0. Therefore, the oxidation number of each sulfur atom in \(\mathrm{S}_{3}\) is 0.
Final Answer
Oxidation number of Na: \(\boxed{0}\)
Oxidation number of \(\mathrm{K}^{+}\): \(\boxed{+1}\)
Oxidation number of \(\mathrm{S}_{3}\): \(\boxed{0}\)