To solve the system of linear equations, we can use a method such as substitution or elimination. Here, we'll use the elimination method to eliminate one of the variables by adding or subtracting the equations. This will allow us to solve for one variable, and then substitute back to find the other variable.
Step 1: Set Up the Equations
We start with the system of equations:
\[
\begin{align*}
& \quad x + 2y = 6 \\
& \quad 3x - y = -10
\end{align*}
\]
Step 2: Solve for One Variable
From the first equation, we can express \( x \) in terms of \( y \):
\[
x = 6 - 2y
\]
Step 3: Substitute and Solve
Substituting \( x \) into the second equation:
\[
3(6 - 2y) - y = -10
\]
Expanding this gives:
\[
18 - 6y - y = -10
\]
Combining like terms results in:
\[
18 - 7y = -10
\]
Solving for \( y \):
\[
-7y = -10 - 18 \\
-7y = -28 \\
y = 4
\]
Step 4: Find the Other Variable
Now substituting \( y = 4 \) back into the expression for \( x \):
\[
x = 6 - 2(4) \\
x = 6 - 8 \\
x = -2
\]
Final Answer
The solution to the system of equations is:
\[
\boxed{x = -2, y = 4}
\]