Questions: A rectangle has a length of 17 inches less than 7 times its width. If the area of the rectangle is 2204 square inches, find the length of the rectangle.
Transcript text: A rectangle has a length of 17 inches less than 7 times its width. If the area of the rectangle is 2204 square inches, find the length of the rectangle.
Solution
Solution Steps
Step 1: Set Up the Equation
Given that the length \( l \) of the rectangle is 17 inches less than 7 times its width \( w \), we can express this relationship as:
\[
l = 7w - 17
\]
The area \( A \) of the rectangle is given as 2204 square inches, which leads to the equation:
\[
A = l \cdot w = 2204
\]
Substituting the expression for \( l \) into the area equation gives:
\[
(7w - 17) \cdot w = 2204
\]
Step 2: Form the Quadratic Equation
Expanding the equation results in:
\[
7w^2 - 17w - 2204 = 0
\]
This is a standard quadratic equation in the form \( ax^2 + bx + c = 0 \) where \( a = 7 \), \( b = -17 \), and \( c = -2204 \).
Step 3: Solve the Quadratic Equation
To find the values of \( w \), we calculate the discriminant:
\[
D = b^2 - 4ac = (-17)^2 - 4 \cdot 7 \cdot (-2204) = 62001
\]
Since the discriminant is positive, we can find two possible solutions for \( w \):
\[
w = \frac{-b \pm \sqrt{D}}{2a} = \frac{17 \pm \sqrt{62001}}{14}
\]
Calculating the two possible values for \( w \):
\[
w_1 = \frac{17 + \sqrt{62001}}{14} \quad \text{and} \quad w_2 = \frac{17 - \sqrt{62001}}{14}
\]
Since \( w_2 \) will yield a negative value, we discard it and take \( w_1 \).
Step 4: Calculate the Length
Using the positive width \( w_1 \), we can find the length \( l \):
\[
l = 7w - 17
\]
Substituting \( w_1 \) into this equation gives us the length of the rectangle.
Final Answer
The length of the rectangle is:
\[
\boxed{l = 116.0 \text{ inches}}
\]