Questions: A table representing the function (f(x)=2left(frac32right)^x) is shown below.
x f(x)
0 2
1 3
2 4.5
3 6.75
What is true of the given function?
- The function increases at a constant additive rate.
- The function increases at a constant multiplicative rate.
- The function has an initial value of 0.
- As each (x) value increases by 1, the (y) values increase by 1.
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Assignment
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Practice with exponential growth functions.
A table representing the function $f(x)=2\left(\frac{3}{2}\right)^{x}$ is shown below.
\begin{tabular}{|c|c|}
\hline $\boldsymbol{x}$ & $\boldsymbol{f}(\boldsymbol{x})$ \\
\hline 0 & 2 \\
\hline 1 & 3 \\
\hline 2 & 4.5 \\
\hline 3 & 6.75 \\
\hline
\end{tabular}
What is true of the given function?
The function increases at a constant additive rate.
The function increases at a constant multiplicative rate.
The function has an initial value of 0 .
As each $x$ value increases by 1 , the $y$ values increase by 1 .
Solution
Solution Steps
Step 1: Analyze the Function
The given function is \( f(x) = 2\left(\frac{3}{2}\right)^{x} \). This is an exponential function, where the base of the exponent is \(\frac{3}{2}\).
Step 2: Determine the Type of Growth
Exponential functions increase at a constant multiplicative rate, not an additive rate. The base \(\frac{3}{2}\) indicates that for each increase in \(x\) by 1, the function value \(f(x)\) is multiplied by \(\frac{3}{2}\).
Step 3: Evaluate the Initial Value
The initial value of the function is the value of \(f(x)\) when \(x = 0\). Substituting \(x = 0\) into the function:
The function does not increase by a constant additive amount. Instead, it increases by a constant multiplicative factor of \(\frac{3}{2}\) as \(x\) increases by 1.
Final Answer
The function increases at a constant multiplicative rate. \(\boxed{\text{The function increases at a constant multiplicative rate.}}\)