Questions: The cheerleaders at a football game launch T-shirts into the crowd from the back of a golf cart that is 2 feet off the ground. The T-shirts have an upward velocity of 30 feet per second. Using the function y=-16 t^2+30 t+2, which of the following correctly identifies the vertex of the parabola and best explains its meaning? (1 point)
The vertex is at (16.063,0.9375). The shirts will reach a maximum height of roughly 0.928 feet.
The vertex is at (0.9375,16.063). The shirts will reach a maximum height of roughly 0.928 feet.
The vertex is at (16.063,0.938). The shirts will reach a maximum height of roughly 16 feet.
The vertex is at (0.9375,16.063). The shirts will reach a maximum height of roughly 16 feet.
Transcript text: The cheerleaders at a football game launch T-shirts into the crowd from the back of a golf cart that is 2 feet off the ground. The $T$-shirts have an upward velocity of 30 feet per second. Using the function $y=-16 t^{2}+30 t+2$, which of the following correctly identifies the vertex of the parabola and best explains its meaning? (1 point)
The vertex is at $(16.063,0.9375)$. The shirts will reach a maximum height of roughly 0.928 feet.
The vertex is at $(0.9375,16.063)$. The shirts will reach a maximum height of roughly 0.928 feet.
The vertex is at $(16.063,0.938)$. The shirts will reach a maximum height of roughly 16 feet.
The vertex is at $(0.9375,16.063)$. The shirts will reach a maximum height of roughly 16 feet.
Solution
Solution Steps
Step 1: Identify the Vertex of the Parabola
The given function is \( y = -16t^2 + 30t + 2 \). This is a quadratic function in the form \( y = at^2 + bt + c \), where \( a = -16 \), \( b = 30 \), and \( c = 2 \).
The vertex of a parabola given by \( y = ax^2 + bx + c \) can be found using the formula for the time at which the vertex occurs: