Questions: 5. The maximum number of electrons in a) n=3 18 b) 4 d 10 c) One orbital by the name of 3 p Q d) Shell 4 e) Subshell g 6. Write an chemical equation that goes with... a) heat of combustion of Mg . b) heat of formation of PBr3(s) c) First ionization energy of Na .

Solution Steps

To find the maximum number of electrons, we use the following rules:

• For a given principal quantum number \( n \), the maximum number of electrons is \( 2n^2 \).
• For a given subshell (s, p, d, f, g), the maximum number of electrons is determined by the formula \( 2(2l + 1) \), where \( l \) is the azimuthal quantum number.

a) For \( n = 3 \): \[ \text{Maximum number of electrons} = 2n^2 = 2(3^2) = 18 \] \(\boxed{18}\)

b) For the \( 4d \) subshell: \[ \text{Maximum number of electrons} = 2(2l + 1) = 2(2 \cdot 2 + 1) = 2(5) = 10 \] \(\boxed{10}\)

c) For one orbital in the \( 3p \) subshell: \[ \text{Maximum number of electrons in one orbital} = 2 \] \(\boxed{2}\)

d) For shell 4 (\( n = 4 \)): \[ \text{Maximum number of electrons} = 2n^2 = 2(4^2) = 32 \] \(\boxed{32}\)

e) For the \( g \) subshell (\( l = 4 \)): \[ \text{Maximum number of electrons} = 2(2l + 1) = 2(2 \cdot 4 + 1) = 2(9) = 18 \] \(\boxed{18}\)

Final Answer